Study 103

Á. Rusz
Internet (RCS blog)
2016
- after C. Poisson -

White wins

1. Rb7+! 1. c7? Qd4+ fork 2. Kb8 Qxg7 = 1... Ka5! 1... Kc5 2. c7 Qa3+ 3. Kb8 +- White wins because of the closed a3-f8 diagonal: Qf8 is not possible.; 1... Kc4 2. Be6+ (2. c7? Qa3+ 3. Kb8 Now the a3-f8 diagonal is open. 3... Qf8! 4. Rb1 Kc5 5. Kb7 Qf3+ 6. Kb8 Qf8 positional draw) 2... Kc5 3. c7 Qa3+ 4. Kb8 +- 2. c7 Qd4+ 2... Qd7!? 3. Kb8 (3. Bxd7? stalemate) 3... Qe8 4. Rb3! Qf8 5. Rb2! Qh8 6. Rd2 +- see the main line.

3. Ka8!! Triangulation! Thematic try: 3. Kb8? Qh8! mutual zugzwang 4. Rb1 Qg8! mutual zugzwang 5. Rb2 (5. Rd1? Qb3+ = fork) 5... Qf8! mutual zugzwang 6. Rb3 (6. Rd2 Qb4+ +- fork) 6... Qe8! 7. Rb7 (7. Rd3 Qb5+ = fork) 7... Qh8 positional draw featuring four pairs of corresponding squares!

3... Qh8 4. Kb8 mutual zugzwang 4. Rb8? Qe5! (4... Qg7? 5. Bd7! Qxd7 6. c8=Q +-) 5. Rb7 Qe8! Triangulation 6. Kb8 Qh8! =

2x2 white cluster

4... Qg8 5. Rb1! mutual zugzwang 5... Qf8! 6. Rb2! mutual zugzwang. It is still too early to switch the rook to the d-file. 6. Rd1? Kb6 = The d6 square is protected! 6... Qh8 The queen has to abandon the protection of the b4 and d6 squares. 7. Rd2! Black doesn't have the Qb4+ fork anymore. 7... Kb6 8. Rd6+ The queen is not protecting d6. 8... Kc5 9. Rd8 The rook unpins the bishop. 9... Qb2+ 10. Bb7 +-

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Related studies: Study 103a