Wednesday, 13 December 2017

Study 138

Árpád Rusz
Zadachy i Etyudy
2017

White wins

1. Bg7+ White cannot capture the a1 bishop immediately because the f8 bishop is also hanging: 1. Kxa1? Rxf8 = 1... Kd5 2. Bxa1! 2. Kxa1? fails because the bishop from g7 would become again a good target for the rook. 2... f2 3. Ng3! Rf5! 4. Be2 Rg5 5. Nf1 Rxg7 = 2... f2 3. Ng3! 3. Nxf2? Rxf2 = 3... f1=Q+ 4. Nxf1 Rxf1+

5. Kb2!! A surprising move which closes the bishop on the corner. Thematic try: 5. Ka2? Rxa1+! with check 6. Kxa1 Kc4 = 5... Rxa1 without check! 5... Kc4 6. Be2+ +-; 5... Re1 6. Bf7+ Kc6 7. Bc4 +-; 5... Rf5 6. Bd1 Kc4 7. Ka3 Rf1 8. Be2+ +- 6. Bf7+! 6. Kxa1? Kc4 = 6... Kc6 7. Be8+! 7. Kxa1? Kb5 = 7... Kd5 8. Kxa1 Kc4 9. b5! +-

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Tuesday, 12 December 2017

Study 137

Árpád Rusz & Martin Minski
JPA-85 JT
2017
Special Commendation

White wins

1. a7! Qd8! 1... Qxa7 2. Bf7+ Kd7 (2... Ke7 3. Nc6+ +-) 3. Qa4+ Kc7 4. Qc6+ Kb8 5. Qe8+ Kc7 6. Qxe5+ Kb6 7. Nc4+ +-; 1... b1=Q 2. Qxb1 (2. axb8=Q+? Qxb8 3. Nc6 Qc7 4. Qa8+ Kd7 5. Qf8 Be6+ =) 2... Qxb1 3. a8=Q+ +- 2. a8=Q 2. a8=R? Bc8 3. Ra7 Bd7 (3... Qg5+? 4. Rg7 +-) 4. Ra8 Bc8 positional draw 2... Be6+! 3. Kg7! 3. Bxe6? Qxa8 = 3... Qxa8 4. Qa4+ 4. Bxe6? Ke7! 5. Bg4 Qf8+ =; 4. Bxa8?? Bxa2 -+ 4... Bd7

5. Nc6!! Cross Theme 5. Qb3? b1=Q! (5... Qxa5? 6. Qb8+ Qd8 (6... Ke7 7. Qf8#) 7. Bf7+ Ke7 8. Qxe5+ Be6 9. Qxe6#) 6. Qxb1 Qxd5 = 5... Qxa4 5... Bxc6 6. Bxc6+ +-; 5... Qxc6 6. Bxc6 b1=Q 7. Qa8+ Ke7 8. Qf8+ +- 6. Bf7#

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Study 136

Árpád Rusz
JPA 85 JT
2017
Special Honourable Mention

Draw

Black has twice as much material than white so it looks very natural to start with a queen promotion: 1. e8=Q? a2 2. Rf6+ Kg2+ 3. Kc2 3. Kc4 Ra4+! 4. Qxa4 Rh4+ -+ 3... a1=N+! Black chooses to promote the pawn to a knight! 3... Rc3+? 4. Kd2 Rd5+ 5. Ke2 Rc2+ 6. Ke3 Rc3+ 7. Ke2 =

Variation A:

4. Kb2 Rb3+ 5. Kc1 Rc5+ 6. Kd2 6. Kd1 Rb1+ 7. Ke2 Rc2+ 8. Kd3 Rd1+ 9. Ke3 Re1+ -+ 6... Rc2+ 7. Kd1 Rb1#


echo checkmate
Variation B:

4. Kd1 Rh1+ 5. Kd2 Ra2+ 6. Kd3 Rd1+ 7. Kc3 Rc2+ 8. Kb4 Rb1+ 9. Ka3 Rb3+ 10. Ka4 Ra2#


echo checkmate

Let's go back to the initial position of the study.


The actual solution starts with a surprising sacrifice: 1. Rh6!! a2! 1... Rxh6 2. e8=Q a2 3. Qf7+! (3. Qf8+? Kg2 4. Qg7+ (4. Qxh6 a1=Q -+) 4... Rg6 5. Qb2+ Kh3 6. Qc3+ Rg3 -+) 3... Kg2 4. Qb7+! Kg1 5. Qg7+ Rg6 6. Qd4+ = 2. Rxh3+ Kg2

3. Rh1!! 3. e8=Q? a1=Q 4. Qe4+ Kxh3 5. Qf3+ Kh4 6. Qf4+ Kh5 -+ 3... Kxh1 3... Re5 4. Ra1 Rxe7 5. Rxa2+ Kg3 6. Ra5 Rc7 7. Rd5! Kg4 8. Rd4+ Kg5 9. Rd5+ Kg6 10. Rd6+ Kg7 11. Rd5! Rc6 12. Kb4! Kg6 13. Kb5 Rc8 14. Rd6+ Kg5 15. Rd5+ Kg4 16. Rd4+ Kg3 17. Rd3+ (17. Rd5? Rh8 -+) 17... Kg4 18. Rd4+ Kg5 19. Rd5+ Kg6 20. Rd6+ perpetual check) 4. e8=Q Finally, the pawn promotes to a queen. 4... a1=Q 5. Qe4+ Kh2 6. Qh4+ Kg2 7. Qg4+ Kf2 8. Qf4+ Ke2 9. Qe4+ Kd2 9... Kf2 10. Qf4+ Kg2 11. Qg4+ Kh2 12. Qh4+ perpetual check 10. Qd4+! Qxd4 stalemate

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Monday, 11 December 2017

Study 135

Árpád Rusz
Sachova Skladba
2017

Draw

1. Nf7 1. Nxg6? Bxg6 2. f5 Bxf5 -+ 1... Kb7 2. Ne5 Bf5 3. Nc4 Kc6! 3... a2 4. Kb2 = 4. Nxa3 Kc5 5. Kb2! 5. Nc2? Bxc2 6. Kxc2 Kc4! zz (6... Kd4? 7. f5! gxf5 8. Kd2 zz Ke4 9. Ke2 zz Kf4 10. Kf2 zz Kg4 11. Kg2 zz f4 12. Kf2 f3 13. Kf1 Kg3 14. Kg1 zz f2+ 15. Kf1 zz Kf3 stalemate) 7. Kd2 Kd4 8. Ke2 Ke4 9. Kf2 (9. f5 gxf5 -+) 9... Kxf4 10. Kg2 Kg4! (10... g5? 11. Kf2 Kg4 12. Kg2 Kh4 13. Kh2 g4 14. Kg2 g3 15. Kg1 Kh3 16. Kh1 g2+ 17. Kg1 Kg3 stalemate) 11. Kh2 Kf3 12. Kh3 g5 13. Kh2 g4 14. Kg1 Kg3! 15. Kh1 Kf2 -+ 5... Kb4

6. Ka1!! mutual zugzwang. Thematic try: 6. Ka2? Be4! mutual zugzwang 7. Kb2 Bd3! -+ mutual zugzwang 6... Be4 6... Kxa3 stalemate 7. Ka2! Bd3 8. Kb2 Bf5 9. Ka1! positional draw - fortress


corresponding squares(K/B)

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Study 134

Árpád Rusz
Dvoretsky MT
2017
Commendation

White wins

1. a7 Kf1! Black avoids moving to f3 because that square is on the long diagonal. 2. Re7! Logical try: 2. Re8? c4 3. Rb8 Rb3! 4. Rxb3 cxb3 5. Kb8 b2 6. a8=Q No check! b1=Q+ = 2... Kf2 Now white has to lose a tempo.


cyclic zugzwang - WTM

3. Rb7 Ra5 4. Rc7! 4. Kb8? Ke3 5. Rc7 Kd4 = 4... Rb5 4... Ke3 5. Kb7 Kd4 6. Rc6! (6. Kb6? Ra1 7. Rxc5 Rxa7! =) 6... Rxa7+ 7. Kxa7 +- 5. Re7 White has transferred the move to black.


cyclic zugzwang - BTM

5... Kf3 Now it was unavoidable for the black king to step on the long diagonal. 5... Kf1 6. Rb7 Ra5 7. Rb2/Kb8 +- 6. Re8! Now that the black king was lured to f3 the main plan works! 6... c4 6... Kf2 7. Rb8 Ra5 8. Kb7 Ke3 9. Rc8 Kd3!? 10. Rxc5! +- (10. Kb6? Rxa7 11. Kxa7 c4 =) 7. Rb8 Rb3 8. Rxb3+ cxb3 9. Kb8 b2 10. a8=Q+ +- The queen has promoted with check!

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Thursday, 9 November 2017

Study 133

Árpád Rusz
Internet (RCS blog)
2017

Draw (DUPLEX)

Although at first glance the initial position seems like a mutual zugzwang, there is a way to achieve draw.
1. Nf2! Thematic try: 1. Ng3? Bxg3 2. Bd8 Bxf4 3. Bf6 Bc1 4. Bxg7+ Kxg7 5. f4 Bxb2+! -+; 1. Be1? Bxe1 2. Nf2 Nc7/Nb6 3. Nh3 Bh4 4. Ng5 Bxg5 5. fxg5 Nb5/Nd5 6. f4 Nc3! 7. bxc3 dxc3 -+ 1... Bxf2 2. Bd8 Be3 3. Bf6! Bc1 3... gxf6 4. exf6 = 4. Bxg7+! Kxg7 5. h8=Q+ 5. h8=R? Bxb2+! -+ 5... Kxh8 6. g7+ Kh7 7. g8=Q+ Kxg8 stalemate

If black is to move in the initial position we have a similar solution. The only move that draws is 1... Nc7! Thematic try: 1... Nb6?

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Thursday, 2 November 2017

Study 37a

V. Vlasenko
Malyshko-105 MT
2017

White wins

Thematic try: 1. Rf8+? Kg2 2. Rg6+ Kh1 3. Rf1+ Qg1 4. Ra1! Qxa1 5. Bxa1 c3+ 6. Kc1 c2 =

With the rook on g6, the g7 square cannot be used as a cutting point to avoid stalemate and there is no time for the critical move Rg6-g8.

Solution: 1. Rf6+! Kg2 2. Rg8+ Kh1 3. Rf1+ Qg1 4. Ra1! 4. Ke2? Qxf1+ 5. Kxf1 stalemate 4... Qxa1 5. Bxa1 c3+ 6. Kc1! mutual zugzwang 6. Bxc3? stalemate 6... c2 This time the rook is already on its right place so the stalemate can be avoided!


pseudo-Indian

7. Bg7! Kg2 8. Be5+ +-

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Related studies: Study 37

Wednesday, 1 November 2017

Study 132

Árpád Rusz
Moscow Ty
2017
1st Prize

White wins

1. Ke4! Kc1! 1... Rh1 2. Rxg2 Rxh3 3. Kxf4 Rh1 4. Rf2 +- 2. Kf3 Rh1 3. Kxg2! f3+! 4. Kxf3

In this position, black has to natural continuations:

a. 4... Rxh3+


dual avoidance

5. Kg4! 5. Ke4? Rg3! 6. Kf4 Rd3! 7. Rf2 (7. Re7 Rd1! 8. Rxf7 Rf1+ =) 7... Rd2! 8. Rf3 (8. Rxd2 Kxd2 9. Kf5 Ke3 10. Kf6 Kf4 =; 8. Rf1+ Kc2 9. Ke5 Rg2 10. Kf6 Kd3 11. Rf5 Ke4 =) 8... Rd7 9. Ke5 Kd2! 10. Kf6 Rd5! (10... Ke2? 11. Rf5 Ke3 12. Kg7 Ke4 13. Rxf7 Rxf7+ 14. Kxf7 Kf5 15. g6 +-) 11. Rf5 Rxf5+ 12. Kxf5 Ke3 13. Kf6 Kf4 = 5... Kd1! counter-attack 5... Rh7 6. Kf5 Kd1 7. Re5! +- The white rook has managed to defend the pawn from the fifth rank.

6. Re6!! Thematic try: 6. Re7? Rh7 7. Kf5 Rg7 8. Kf6 Rg6+ 9. Kf5 Rg7 = Positional draw. Attacking the black pawn with Re7 fails because black has the Rg7 defence. In the main line white will try to attack the black pawn from the opposite direction by bringing its rook to h7. To conquer the h-file, white has to bring its rook to h6 on the shortest way. That is the reason for the surprising sacrifice on e6!; 6. Rf2? Rh7 7. Kf5 Ke1 8. Ra2 Rh3! 9. Kg4 (9. Ra7 Rf3+ 10. Kg4 Rf2! =) 9... Rh7 10. Kf5 Rh3 positional draw; 6. Kxh3? Kxe2 = 6... Rh7! 6... fxe6 7. Kxh3 +-; 6... Rh1 7. Rf6 Rg1+ 8. Kf5 Rf1+ 9. Ke5 Rg1 10. Rf5 Ke2 11. Kf6 +- 7. Rh6! Rg7 7... Rxh6 8. gxh6 +- 8. Kf5 Ke2 9. Kf6 Rg8 10. Rh7! 10. Rh5? Kf3 11. Kxf7 Kg4! = counter-attack 10... Rg6+ 10... Kf3 11. Rxf7 Kg4 12. g6 Kh5 13. Rh7+ +- 11. Kf5 +- In contrast with the thematic try, black has no more the move Rg7 to defend.


But what if, before it captures the h3 pawn, black inserts a king move?

b. 4... Kd1!? 5. Rf2! We already know from the thematic try that 5. Re7? doesn't win: 5... Rxh3+ 6. Kg4 Rh7 7. Kf5 Rg7 8. Kf6 Rg6+ 9. Kf5 Rg7 positional draw 5... Rxh3+ 5... Ke1 6. Kg2! +-


dual avoidance

6. Ke4! Now 6. Kg4? will fail: 6... Rh7 7. Kf5 Ke1 8. Rf4 The white rook couldn't move to the fifth rank to defend the pawn. 8... Rg7! 9. Kf6 Rg6+! 10. Kf5 Rg7 positional draw 6... Rg3! 6... Rh7 7. Ke5! The white king avoids blocking the f5 square. 7... Ke1 8. Rf5! +- The white rook has managed to defend the pawn on the fifth rank. 7. Kf4 Rg1 8. Ra2! Rf1+ 9. Ke4! 9. Ke3? Rf5 = 9... Re1+ 10. Kd3! Re5 11. Ra1# Surprisingly, 4... Kd1!? also had a negative effect: the black king became exposed to a checkmate attack!

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Study 131

Árpád Rusz
Selivanov-50 JT
2017
3rd Prize

White wins

1. d7 Nd5! 1... Ba4 2. Nc6! +-; 1... Bf5 2. Ne6! +- 2. Ne6! Thematic try: 2. Nc6? Nc7+ 3. Kb6 Ne6 (position X') 4. Nd4! Ba4! = 2... Nb4+ 3. Kb6 Nc6!


position X


position X'

If we compare Position X with Position X' from the thematic try, it appears like the two knights were "repainted". This is the only difference between the two positions so the study features the WCCT-10 Theme in an original way!

4. Nd4! 4. Kxc6? Ba4+ = 4... Bf5! Black goes for a stalemate trap! 4... Nd8 5. Nxc2 +- 5. Nxf5 5. Nxc6? Bxd7 = 5... Nb8! 6. d8=B! +- 6. d8=Q? stalemate

The end position has a white bishop and knight vs. a black knight, while in the initial position of the study there was a white knight vs. black bishop and knight. It looks like during the game, paradoxically, all minor pieces were repainted!

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Tuesday, 24 October 2017

Study 130

Árpád Rusz
EG
2017
after Javier Rodriguez Ibran
- version -

White wins

1. Qd3+ Kc1 1... Rd2 2. Qxb1# 2. R7g2 Bh3! 2... Bf5 3. Re2! +- 3. Ba3! Ne3+! 3... Qg4 4. Qc2# 4. Qxe3+ Qd2 5. Qxd2+ cxd2 6. e8=Q d1=Q+ 7. Qe1!


full point zugzwang

7... Qxe1+ 8. Kxe1 Bxg2 9. Rxg2 zugzwang 9... Ra1 10. Bxb2+ +-

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The study is based on a 10-man aristocratic full point zugzwang discovered by Javier Rodriguez Ibran (EG130, 1998). AFAIK this is the first study to feature this position.

Monday, 23 October 2017

Study 93

Árpád Rusz
Marwitz-100 MT, 2016
Special Prize
- version -

White wins

Now I prefer this more economical initial position of the Study 93a. The main line and the two tries all feature different systematic movements!

1st try: 1.f8Q? Ra7+ 2.Kb8 Rab7+! 2...Rhb7+? 3.Kc8 Rc7+ 4.Kd8 Rd7+ 5.Ke8 Re7+ 6.Qxe7+– 3.Kc8 Rbc7+ 4.Kd8 Rcd7+ 5.Ke8 Rde7+ 6.Qxe7 Rxh8+ 7.Kd7 h2 8.Qf7+ Kb1 9.Qb3+ Kc1= 9...Ka1? 10.Qc3++–

2nd try: 1.Qxg7? Rxg7 2.f8Q h2! 3.Qxf3

3...Rg8+!! Paradoxically, black lets the white king to escape from the eight rank! The immediate 3...Rg1? loses because of a Queen staircase on the a and b-files from b3 to b8! 4.Qb3+ Ka1 5.Qa3+ Kb1 6.Qb4+ Ka1 7.Qa5+ Kb1 8.Qb6+ Ka1 9.Qa7+ Kb1 10.Qb8++– 4.Kb7 Rg1! Another check would be fatal: 4...Rg7+? 5.Kc8!! Back to the 8th rank! (5.Kc6? Rg1 6.Qb3+ Ka1 7.Qa3+ Kb1 8.Qb4+ Ka1 9.Qa5+ Kb1 10.Qb6+ Kc1!=) 5...Rg8+ 6.Kd7!+– 5.Qb3+ Ka1 6.Qa3+ Kb1 7.Qb4+ Ka1(2) 8.Qa5+ Kb1 9.Qb6+ Ka1(2) 10.Qa7+ Kb1(2)=

Main: 1.Qxh7! Rxh7

2.f8Q f2! 2...h2 6.Qg8++– 3.Qxf2 3.Qg8+? Ka1! 4.Qxh7 f1Q=; 3.c4? Rh8! 4.Qxh8 f1Q= 3...h2 4.c4+ Kb3 5.Qf3+ Kb4! 5...Kxc4 6.Qe4++– 6.Qh1 Kc5!

The plan that looks logical now is starting to move with the white king towards the rook. But it doesn't work yet! While the black king is on c5 the rook can leave the seventh rank (e.g. by moving to h5). 7.Qd5+ Kb4 8.Qd2+ Kc5 9.Qf2+ Kb4 10.Qb2+ Kc5 11.Qb5+ Kd4 12.Qd5+ Kc3 13.Qh1 Kd4 The black king is not on c5 so the white king can make a move towards the rook! 14.Kb8! The first step. 14...Kc5 Back to c5... White needs to repeat the manoeuvre to gain a tempo for another king move.

15.Qd5+ Kb4 16.Qd2+ Kc5 17.Qf2+ Kb4 18.Qb2+ Kc5 19.Qb5+ Kd4 20.Qd5+ Kc3 21.Qh1 Kd4 22.Kc8! The second step. 22...Kc5

23.Qd5+ Kb4 24.Qd2+ Kc5 25.Qf2+ Kb4 26.Qb2+ Kc5 27.Qb5+ Kd4 28.Qd5+ Kc3 29.Qh1 Kd4 30.Kd8! The third step. 30...Kc5

31.Qd5+ Kb4 32.Qd2+ Kc5 33.Qf2+ Kb4 34.Qb2+ Kc5 35.Qb5+ Kd4 36.Qd5+ Kc3 37.Qh1 Kd4 38.Ke8! The fourth step. 38...Kc5

39.Qd5+ Kb4 40.Qd2+ Kc5 41.Qf2+ Kb4 42.Qb2+ Kc5 43.Qb5+ Kd4 44.Qd5+ Kc3 45.Qh1 Kd4 46.Kf8! The fifth step. 46...Kc5

47.Qd5+ Kb4 48.Qd2+ Kc5 49.Qf2+ Kb4 50.Qb2+ Kc5 51.Qb5+ Kd4 52.Qd5+ Kc3 53.Qh1 Kd4 54.Kg8! +- The last step along the 8th rank.

The white king will finally escape from the last rank. White has a winning position. Notice that this was the 50th move since the last capture or pawn move (4.c4+), so according to the FIDE rules, this position would be a draw! Fortunately, endgame study composition codex doesn't care about that artificial "draw by 50 moves" rule!

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Wednesday, 18 October 2017

Study 129

Michael Byrne & Árpád Rusz
Shakhmatnaya Kompozitsia
2017

White wins

1. Ka5! 1. Kb5? Bd3+! 2. Rxd3 Rxc1 = 1... Bc2! 2. Bxa3! 2. Rxa1+? Kxa1 3. Bxa3 b2 = 2... Kxa3 3. R1xc2! 3. Rxa1+? Kb2 = fork

Main 1:
3... Ra2 4. Rc1 Rg2!


5. Rf3!!

Thematic try: 5. Rh3? Rg5+ 6. Kb6 Rg6+ 7. Kb5 Rg5+ 8. Kc4 Ka2 9. Kb4 Rg4+ 10. Kc3 b2 11. Rc2 Ka1! 12. Rxb2 Rg3+! 13. Rxg3 stalemate 5... Rg5+ 6. Kb6 Rg6+ 7. Kb5 Rg5+ 8. Kc4 Ka2 9. Kb4 Rg4+ 10. Kc3 b2 11. Rc2 Ka1 12. Rxb2 +-

Main 2:
3... Rh1


4. Rf2!!

1st thematic try: 4. Rg2? Rh3 5. Rc4 Rh5+ 6. Ka6 Rh3/Rh6(8) 7. Kb5 Rh5+ 8. Kc6 Rh6+ 9. Kd5 Rh5+ 10. Ke6 Rh6+ 11. Kf5 Rh5+ 12. Kg6 (12. Kf6 Rh6+ 13. Kg5 Rh8! 14. Kf6 Rh6+ positional draw) 12... Rb5 13. Rg3 Ka2 14.Ra4+ Kb1 15. Rg1+ Kb2 16. Kf6 Rc5 17. Ke6 Rc1 18. Rg3 Rc3 19. Rg8 Kb1 20. Ra3 Kb2 21. Rga8 Kc2 = Position X'. The white king is too far to help.

4... Rh3! 5. Rc4 5. Rxh3? stalemate 5... Rh5+ 6. Ka6! 6. Kb6? b2 7. Rf3+ Ka2 8. Ra4+ Kb1 9. Rf1+ Kc2 10. Rb4 Kc3 = 6... Rh3 6... b2 7. Rf3+ Ka2 8. Ra4+ Kb1 9. Rf1+ Kc2 10. Rb4 Kc3 11. Rb8 +- 7. Kb5 Rh5+ 8. Kc6 Rh6+ 9. Kd5/Kc(d)7 9... Rh5+ 10. Kd(e)6 10... Rh6+ 11. Ke5(7) 11... Rh5+ 12. Kf6 Rh8! 13. Kf7! 13. Kg7? Rb8 = 13... Rh7+ 14. Kg6 Rb7 15. Rf3 Ka2 16. Ra4+ Kb1 17. Rf1+ Kb2! 17... Kc2 18. Rc4+ Kd3 19. Rcc1 b2 20. Rfd1+! Ke2 21. Rb1 +- 18. Kf6! Rc7 19. Ke5! In contrast to the thematic try, there was no rook protecting the fifth rank. 19... Rc1 20. Rf3 Rc3 21. Rf8! White doesn't allow a black counterplay based on Rc8. 21... Kb1 22. Ra3! The only way to stop the pawn is by pinning. 22... Kb2 23. Rfa8 2nd thematic try: 23. Kd4? Rh3! 24. Ra7 Rh4+ 25. Ke5 Rh5+ 26. Kf4 Kb1! Black uses the poor position of the f8 rook which is obstructed by its own king. 27. Rb8 b2 = This try failed only because the rook was on the f-file so white will start a manoeuvre to reposition the rook to another file. 23... Kc2 Position X. Now the white king is closer compared to Position X' reached in the 1st thematic try.


Position X


Position X'

24. Kd4! Rd3+ 25. Ke4! White leaves the c-file open for a rook check. 25. Kc4? b2 26. Rxd3 b1=Q = 25... Rc3 26. Rg(h)8 Kb2 26... b2 27. Rg2+ Kd1 28. Rxc3 b1=Q+ 29. Rd3+ Ke1 30. Rg1+ +- 27. Kd4! Unlike the 2nd thematic try, now that the rook was repositioned from f8, this plan works.27...Rc2! Although the best square for the black rook is c1, black deliberately wastes a tempo before putting it there trying to play for a zugzwang. 28. Rga8 28. Ra4? Kb1 29. Rc4 b2 = Now we see the reason for moving the black rook to c2 instead of c7. With an unprotected rook, this pawn move wouldn't be possible. 28... Rc1 The threat 29.Ra1 had to be stopped. Now white seems to be in zugzwang but it still can win by transferring the move to black.


cyclic zugzwang - WTM

29. R3a4(5,6,7) White threatens to put a rook to the b-file. Beside occupying the first rank, this is white's other plan to win. 29... Kb1! Black aims for a fortress by trying to push the pawn. 30. Ra1+ 30. Rb7? b2 = fortress 30... Kb2 31. R1a3!


cyclic zugzwang - BTM

31... Rh1 Black has to keep the rook on the first rank. 32. R3a5(6,7) 32... Kb1 This is the last try to build the fortress. Now that the black rook has moved from c1, this move loses immediately. 33. Ra1+ +-

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Saturday, 14 October 2017

Study 128a

A. Stavrietsky
Babich-Olimpiev MT
2017
1st Prize

Draw

1. Nd5 1. Qxh6+? Rh7 -+ 1... Rc4+ 2. Kb1 2. Kb2? Rxe4 3. Nxe7 Rf2+ 4. Kb1 Bxh5 -+ 2... Rc1+! 3. Kb2 3. Kxc1? Qa3+ -+ 3... Rf2+ 4. Nxf2 Rb1+! 5. Kxb1 Qh7+ 6. g6! 6. Kb2? Bxh5 7. Bxe5+ Ng7 8. Ne7 hxg5 -+ 6... Bxg6+ 7. Bc2!! bxc2+ 8. Kc1 Bxh5 9. Bxe5+ Ng7 10. Ne7! Bg4! 11. h4 11. Bf4? Bh3! 12. Be5 h5 13. Bf4 h4 -+ 11... h5 12. Bf4 Ne8 13. Be5+ Ng7 14. Bf4 Bd7 15. Bd2! 15. Bg5? Ne8 -+ 15... Ne6 16. Bc3+ Ng7 17. Bd2 Ba4 18. Bf4! positional draw

Related study: Study 128